Respuesta :

skyluke89
Silver is a very good conductor, this means its resistivity is very low (from table, we can check the precise value, which is [tex]\rho_s = 1.6 \cdot 10^{-8} \Omega m[/tex]).

Pure water, instead, is a very bad conductor, this means its resistivity is very high, of order of [tex]k \Omega \cdot m[/tex] ([tex]10^3 \Omega m[/tex] ). Even without knowing the precise value of the pure water resistivity, we can estimate the ratio between the pure water resistivity and the silver resistivity by comparing the two orders of magnitude:
[tex]r= \frac{10^3 \Omega m}{10^{-8} \Omega m} \sim 10^{11} [/tex]

Therefore, we can say that the correct answer is
[tex]3 \cdot 10^{11} : 1[/tex]
snehashish65

The resistivity is a dependent factor for the ease of allowing electrons to flow. The approximate ratio of the resistivity of pure water to silver is [tex]3 \times 10^{11} :1[/tex].

What is Resistivity?

The property of the material that determines the actual resistance offered by the material to the flow of current through a cross-section area, is known as the resistivity of the material.

Pure water is a bad conductor of electricity which means it offers high resistance to the flow of electric current. So, the standard value of the resistivity of pure water is around [tex]10^{3} \;\rm \Omega.m[/tex].

On the other hand, silver is one of the materials which allows higher conduction of electricity through it, hence it has a lower level of resistivity of the order [tex]1.60 \times 10^{-8} \;\rm \Omega.m[/tex]

So, the ratio of resistivity of water to the silver is,

[tex]=\dfrac{10^{3}}{ 1.6 \times 10^{-8}}\\\\\approx 3 \times10^{11} : 1[/tex]

Thus, we can conclude that the approximate ratio of the resistivity of pure water to silver is [tex]3 \times 10^{11} :1[/tex]

Learn more about electrical resistivity here:

https://brainly.com/question/824149

.

Otras preguntas