At an ocean depth of 10.0 m, a diver’s lung capacity is 2.40 l. the air temperature is 32.0°c and the pressure is 101.30 kpa. what is the volume of the diver’s lungs at the same depth, at a temperature of 21.0°c and a pressure of 141.20 kpa?

At an ocean depth of 10.0 m, a diver’s lung capacity is 2.40 l. the air temperature is 32.0°c and the pressure is 101.30 kpa. The volume of the diver’s lungs at the same depth, at a temperature of 21.0°c and a pressure of 141.20 kpa is 1.66 L.

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aristocles aristocles · Answer 2 · 2019-09-04T02:02:39+02:00

Answer:

V = 1.66 L

Explanation:

As we know that at the depth of 10 m the volume of the lungs of diver is given as

V = 2.40 L

Temperature = 32 degree C

Pressure = 101.30 kPa

Now we have change the values of pressure and temperature

Pressure = 141.20 kPa

Temperature = 21 degree C

Now we can use idea gas equation to solve this

[tex]PV = nRT[/tex]

[tex]\frac{P_1V_1}{RT_1} = \frac{P_2V_2}{RT_2}[/tex]

so we have

[tex]\frac{101.30 \times 2.40}{R(273 + 32)} = \frac{141.20 \times V}{R(273 + 21)}[/tex]

[tex]V = 1.66 L[/tex]