Costs for standard veterinary services at a local animal hospital follow a normal distribution with a mean of $88 and a standard deviation of $24. what is the probability that one bill for veterinary services costs between $42 and $133?
the probability that one bill for veterinary services costs between $42 and $133 will be given as follows P(42<x<133) z=(x-μ)/σ where: μ-mean σ-standard deviation thus when x=42: z=(42-88)/24=-1.92 thus P(x<42)=0.0281
when x=133 x=(133-88)/24=1.875 thus P(x<133)=0.9699 Thus P(42<x<133) =0.9699-0.0281 =0.9418
