Hello!
We have the following data:
W (molality) = ? (in Molal)
m1 (mass of the solute) = 14.7 g
m2 (mass of the solvent) =? (in Kg)
d (solvent density) = 1,00 g/mL
V (volume of the solvent) = 150 mL
The mass of the solvent will be found by the following formula
[tex]d = \dfrac{m_2}{V} [/tex]
[tex]1 = \dfrac{m_2}{150} [/tex]
[tex]m_2 = 1*150 [/tex]
[tex]m_2 = 150\:g\to \boxed{m_2 = 0,15\:Kg}[/tex]
M1 (Molar mass of solute - C6H12O6) = ?
C = 6*12 = 72 u
H = 12*81 = 12 u
O = 6*16 = 96 u
------------------------
M1 (Molar mass of solute - C6H12O6) = 72+12+96 = 180 g/mol
Now, let's find Molality, applying the above data to the formula, let's see:
[tex]\omega = \dfrac{m_1}{M_1*m_2} [/tex]
[tex]\omega = \dfrac{14,7}{180*0,15}[/tex]
[tex]\omega = \dfrac{14,7}{27}[/tex]
[tex]\boxed{\boxed{\omega \approx 0,54\:Molal}}\end{array}}\qquad\checkmark[/tex]
I hope this helps. =)
