Respuesta :

gmany
Use the trigonomeric function:
[tex]\cos30^o=\dfrac{x}{10}\\\\/\cos30^o=\dfrac{\sqrt3}{2}/\\\\\dfrac{x}{10}=\dfrac{\sqrt3}{2}\ \ \ |\cdot10\\\\x=\sqrt3\cdot5\\\\x=5\sqrt3[/tex]