The prismatic bar has a cross-sectional area
a. If it is subjected to a distributed axial loading that increases linearly from w = 0 at x = 0 to w = w0 at x = a, and then decreases linearly to w = 0 at x = 2a, determine the average normal stress in the bar as a function of x for a < x ≤ 2a.

Respuesta :

solution:

[tex]sum fx=0\\ n=\frac{1}{2}\times\frac{w_{0}}{a}(2a-x)^2\\ n=\frac{w_{0}}{20}(2a-x)^2\\ angle is the normal shus\\ \sigma =\frac{N}{A}\\ \frac{\frac{w_{0}}{2a}(2a-x)^2}{A}\\ \sigma(x)=\frac{w_{0}}{2aA}[2a-x]^2[/tex]