sheb2347
sheb2347 sheb2347
  • 11-09-2018
  • Mathematics
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Please help! 10 points up

Please help 10 points up class=

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gmany
gmany gmany
  • 11-09-2018

[tex]sine=\dfrac{opposite\ leg}{hypotenuse}\to\boxed{B}[/tex]


Other:

[tex]\dfrac{hypotenuse}{opposite\ leg}=cosecant\\\\\dfrac{opposite\ leg}{adjacent\ leg}=tangent\\\\\dfrac{adjacent\ leg}{hypotenuse}=cosine[/tex]

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2021crabtree
2021crabtree 2021crabtree
  • 11-09-2018

the opposite leg/hypotenuse=sine of an angle in a right triangle

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