Answer:
Common difference, d [tex]=\dfrac{1}{8}[/tex]
Step-by-step explanation:
Given: The sequence is arithmetic [tex]\dfrac{1}{4},\dfrac{3}{8},\dfrac{1}{2}[/tex]
[tex]\text{First term, }a_1=\dfrac{1}{4}[/tex]
[tex]\text{Second term, }a_2=\dfrac{3}{8}[/tex]
[tex]\text{Third term, }a_3=\dfrac{1}{2}[/tex]
To find: Common difference, f
Common difference is equal to difference of second term minus first term.( Difference of any two consecutive term)
[tex]\text{Common difference, }d=a_2-a_1=a_3-a_2[/tex]
[tex]d=\dfrac{3}{8}-\dfrac{1}{4}[/tex]
[tex]d=\dfrac{3-2}{8}[/tex]
[tex]d=\dfrac{1}{8}[/tex]
Hence, The common difference of the given arithmetic sequence is [tex]\dfrac{1}{8}[/tex]
