Point S is on YB. YS:SB=4:1, Y(-10,6) and B(10,1). Find coordinates for point S
A.(-6,5)
B.(-2,4)
C.(2,3)
D.(6,2)

Respuesta :

Answer:

The correct option will be:  D. (6, 2)

Step-by-step explanation:

Point [tex]S[/tex] divides the line segment [tex]YB[/tex] in a ratio of [tex]4:1[/tex]

Given that, [tex]Y(-10, 6)[/tex] and [tex]B(10, 1)[/tex]

If a point [tex](x,y)[/tex] divides a line segment with endpoints as [tex](x_{1}, y_{1})[/tex] and [tex](x_{2}, y_{2})[/tex] in a ratio of [tex]m:n[/tex] , then...........

[tex](x, y)= (\frac{mx_{2}+nx_{1}}{m+n},\frac{my_{2}+ny_{1}}{m+n})[/tex]

Here,  [tex](x_{1}, y_{1})=(-10,6)[/tex] and [tex](x_{2}, y_{2})=(10,1)[/tex]

Also,  [tex]m:n=4:1[/tex]

Now plugging the values, we will get........

[tex]x=\frac{4(10)+1(-10)}{4+1}= \frac{40-10}{5}= \frac{30}{5}=6 \\ \\ \\ y=\frac{4(1)+1(6)}{4+1}= \frac{4+6}{5}= \frac{10}{5}=2[/tex]

So, the coordinates for point S will be:  (6, 2)