Respuesta :
[tex]x^2(x+2)(x+6)=0\\\\x^2=0 \vee x+2=0 \vee x+6=0\\\\x=0 \vee x=-2 \vee x=-6[/tex]
Here we need to find the 3 solutions of the equation x^2*(x + 2)*(x + 6) = 0.
The solutions are:
x = 0, x = -2, and x = -6
Let's see how to get the solutions:
First, notice that for an equation like:
A*B*C = 0
We must have:
A = 0, or B = 0, or C = 0.
Notice that our equation x^2*(x + 2)*(x + 6) = 0 has 3 coefficients, we will get one solution by making each one of these equal to zero.
x^2 = 0
x = √0 = 0.
(x + 2) = 0
x = 0 - 2 = -2
(x + 6) = 0
x = 0 - 6 = -6
Then the 3 solutions are:
x = 0, x = -2, and x = -6
If you want to learn more, you can read:
https://brainly.com/question/14400360