Respuesta :

[tex]4x^2-35x+4\\\\a=4;\ b=-35;\ c=4\\\\\Delta=b^2-4ac\to\Delta=(-35)^2-4\cdot4\cdot4=1225-64=1161\\\\x=\frac{-b\pm\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{1161}=\sqrt{9\cdot129}=3\sqrt{129}\\\\x=\frac{-(-35)\pm3\sqrt{129}}{2\cdot4}=\frac{35\pm3\sqrt{129}}{8}\\\\4x^2-35x+4=4\left(x-\frac{35-3\sqrt{129}}{8}\right)\left(x-\frac{35+3\sqrt{129}}{8}\right)[/tex]

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