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The floor of a rectangular deck has a length that is 6 feet more than it’s width, x. Hakeem is building the deck and decided to increase both dimensions by 3 feet. What is the new area, D, of the floor of the deck?

A. x^2 + 12x + 27
B. x^2 + 9x + 18
C. x^2 + 9x
D. x^2 + 6x

Respuesta :

godgirljlo

Im not 100% sure but im like 98% sure that the answer is C. Sorry I couldnt give you a FOR SURE answer but im pretty sure thats the answer. hopefully someone else comes soon to give you the for sure but i think c is the answer.

salatulmaghrib
The original length and width:
Length x + 6
Width x

Hakeem increased both dimensions by 3 feet, so they now are
Length x + 9
Width x + 3

To find the new area, multiply (x + 9) and (x + 3)
It is [tex]x^2 \+ 12x \+ 27[/tex]
So, the answer is A.