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During a one-month sales contest, Joaquin sold 56 cars and Annette sold 49 cars. Which ratio is equivalent to the ratio of the number of cars Annette sold to the number of cars Joaquin sold? A. 56:49 B. 3:4 C. 8:7 D. 98:112

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wegnerkolmp2741o

Answer:

D. 98:112

Step-by-step explanation:

We want to find Annette:Joaquin

49:56

Both of these numbers are divisible by 7. so we need to divide both of them by 7.

7: 8

Now multiply by each side by 14

7*14 : 8*14

98: 112
the answer is 8:7!! When you divide 56:49 by 7 it gives you 8:7 :-)

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