Answer:
Initially he had 200 kg of apples.
Step-by-step explanation:
Let x kg be the amount of apples the farm stand initially had.
During the first hour of operation the farm stand owner sold 15% of the apples he had, then he sold [tex]0.15x[/tex] kg of apples and [tex]x-0.15x=0.85x[/tex] kg of apples left.
On the second hour he sold 20% of the remaining apples, then he sold [tex]0.20\cdot 0.85x=0.17x[/tex] kg of apples and [tex]0.85x-0.17x=0.68x[/tex] kg of apples left.
On the third hour he sold 25% of the remaining apples, then during the third hour he sold [tex]0.25\cdot 0.68x=0.17x[/tex] kg of apples.
If during the third hour he sold 34 kg of apples, then [tex]0.17x=34\Rightarrow x=\dfrac{34}{0.17}=200\ kg.[/tex]
