Respuesta :

Answer:

solution is

[tex](-8,\infty)[/tex]

Step-by-step explanation:

we are given inequality as

[tex]-122<-3(-2-8x)-8x[/tex]

Firstly, we will simplify it

[tex]-122<-3\times -2+3\times 8x-8x[/tex]

[tex]-122<6+24x-8x[/tex]

[tex]-122<6+16x[/tex]

now, we can subtract both sides by 6

[tex]-122-6<6+16x-6[/tex]

[tex]-128<16x[/tex]

now, we can divide both sides by 16

and we get

[tex]\frac{-128}{16}<\frac{16x}{16}[/tex]

[tex]-8<x[/tex]

so, solution is

[tex](-8,\infty)[/tex]