mecca99
contestada

on the xy-plane, the graph of function f has x-intercepts at -3, -1, and 1. which of the following could define f?
A) f(x)= (x-3)(x-1)(x+1)
B) f(x)=(x-3)(x-1)^2
C) f(x)=(x-1)(x+1)(x+3)
D) f(x)=(x+1)^2(x+3)

Respuesta :

x intercept is when y=0
or f(x) = 0
set the f(x)'s to 0
your answer is C
x-1=0 x+1=0  x+3=0
so x= -3, -1, and 1