Correct Answer is
add the river’s velocity to the boat’s velocity
Explanation
In this question we have given ,both current and boat are moving in same direction.
let [tex]V_{C}[/tex] be velocity of current
and [tex]V_{B}[/tex] bw velocity of boat
velocity of current with respect to shore [tex]V_{CS}[/tex]=velocity of current -velocity of shore..............(1)
velocity of boat with respect to river,[tex]V_{BC}[/tex]=velocity of boat-velocity of current.........(2)
add equation (1) and equation (2)
velocity of velocity of current with respect to shore+velocity of boat with respect to river =velocity of current(river) -velocity of shore+velocity of boat-velocity of current(river)
[tex]V_{CS}+V_{BS}=V_{C}-V_{s}+V_{B}-V_{C}\\V_{CS}+V_{BS}=V_{S} +V_{B}\\V_{CS}+V_{BS}=V_{BS}[/tex]
it means velocity of the boat relative to shore=rivers velocity relative to shore+boat velocity relative to river
velocity of the boat relative to shore=[tex]4\frac{km}{h} +5\frac{km}{h}[/tex]
velocity of the boat relative to shore=[tex]9\frac{km}{h}[/tex]