Answer:
[tex]r=\frac{1}{3}(9q+2)[/tex]
Step-by-step explanation:
Given the equation:
[tex]9q-4 = 3r-6[/tex] ...[1]
We have to rearrange the equation so q is the independent variable.
Add 6 to both sides of an equation in [1] we have;
[tex]9q+2= 3r[/tex]
Divide both sides by 3 we have;
[tex]\frac{1}{3}(9q+2) = r[/tex]
or
[tex]r=\frac{1}{3}(9q+2)[/tex]
where, q is the independent variable.
Therefore, the equation in which q is the independent variable is, [tex]r =\frac{1}{3}(9q+2)[/tex]
