Answer:
[tex]\large\boxed{y\leq-7}[/tex]
Step-by-step explanation:
[tex]-8y\geq56\qquad\text{change the signs}\\\\8y\leq-56\qquad\text{divide both sides by 8}\\\\\dfrac{8y}{8}\leq\dfrac{-56}{8}\\\\y\leq-7[/tex]
