Respuesta :
Hello from MrBillDoesMath!
Answer:
a = 1/ (x-3)^2, x <> 3, a > 0
Discussion:
Solve
a(x-3)^2 -1 = 0 => add 1 to both sides
a(x-3)^2 = 1 => divide both sides by (x-3)^2
a = 1/ (x-3)^2
Note: the above solution assumes that x <> 3 ( as we cant't divide by zero) and that a > 0. That is, there is NO solution to the equation is a < 0 as
a = 1/ (x-3)^2 and 1/ (x-3)^2 > 0.
Thank you,
MrB
