Four unequal resistors are connected in series with each other. Which one of the following statements is correct about this combination?A. The equivalent resistance is less than that of the largest resistorB. The equivalent resistance is more than the largest resistanceC. The equivalent resistance is equal to that of any one of the resistors.D. The equivalent resistance is equal to average of the four resistancesE. The equivalent resistance is less than that of the smallest resistor

Respuesta :

Answer:

B. The equivalent resistance is more than the largest resistance

Explanation:

When N resistors are connected in series with each other, the same current flow through them:

[tex]I=I_1 = I_2 = ... =I_N[/tex] (1)

On the contrary, the total voltage of the circuit is equal to the sum of the voltages dropped on each resistor:

[tex]V=V_1+V_2+....+V_N[/tex]

Using Ohm's law, [tex]V=RI[/tex], we can rewrite this equation as

[tex]IR_{eq} = I_1 R_1 + I_2 R_2 + ... +I_N R_N[/tex]

However, we said that (1) the current is the same for each resistor, so we can simplify the previous equation as:

[tex]R_{eq}=R_1 + R_2 + ... + R_N[/tex]

So, the equivalent resistance of N resistors connected in series is equal to the sum of the individual resistances. As a consequence, we have that [tex]R_{eq}[/tex] is always larger than any of the individual resistances, so the correct statement is

B. The equivalent resistance is more than the largest resistance