Calculate the magnitude of the linear momentum for the following cases. (a) a proton with mass 1.67 10-27 kg, moving with a speed of 5.10 106 m/s kg · m/s (b) a 15.0-g bullet moving with a speed of 480 m/s kg · m/s (c) a 72.5-kg sprinter running with a speed of 10.5 m/s kg · m/s (d) the Earth (mass = 5.98 1024 kg) moving with an orbital speed equal to 2.98 104 m/s. kg · m/s

Respuesta :

Answer:

The linear momentum of an object is given by:

p = mv

where

m is the mass

v is the velocity

Let's apply this formula to the 4 cases:

a) proton

m = 1.67 10-27 kg

v = 5.10 10^6 m/s

Momentum: [tex]p=mv=(1.67\cdot 10^{-27} kg)(5.1\cdot 10^6 m/s)=8.52\cdot 10^{-21}kg m/s[/tex]

(b) bullet

m = 15.0 g = 0.015 kg

v = 480 m/s

Momentum: [tex]p=mv=(0.015 kg)(480 m/s)=7.2 kg m/s[/tex]

(c) Sprinter

m = 72.5 kg

v = 10.5 m/s

Momentum: [tex]p=mv=(72.5 kg)(10.5 m/s)=761.3 kg m/s[/tex]

(d) Earth

m = 5.98 10^24 kg

v = 2.98 10^4 m/s

Momentum: [tex]p=mv=(5.98\cdot 10^{24} kg)(2.98\cdot 10^4 m/s)=1.78\cdot 10^{29} kg m/s[/tex]