Answer:
124.3 J/m^3
Explanation:
The energy density between the plates of a parallel-plate capacitor is given by
[tex]u=\frac{1}{2}\epsilon_0 E^2[/tex]
where
ε0 = 8.85 × 10-12 C2/N · m2 is the vacuum permittivity
E is the electric field strength
In this problem,
E = 5.3 × 106 V/m
So the energy density is
[tex]u=\frac{1}{2}(8.85\cdot 10^{-12}F/m) (5.3\cdot 10^6 V/m)^2=124.3 J/m^3[/tex]
