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A 150 g egg is dropped from 3.0 meters. The egg is
moving at 4.4 m/s right before it hits the ground The egg
comes to a stop in 0.072 seconds.
What is the magnitude of force that the ground exerted on
the egg?
0.66 N
9.2N
13N
180 N​

Respuesta :

MathPhys

Answer:

9.2 N

Explanation:

F = ma

F = m Δv / Δt

F = (0.150 kg) (4.4 m/s − 0 m/s) / 0.072 s

F = 9.2 N

deadloxdagger

Answer:

9.2Newtons

Explanation:

Just got it right on edg

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