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What is the specific latent heat of fusion of ice if it takes 863 kJ to convert 4.6 kg of ice into water at 0 C?

Respuesta :

curiousmuktar

Answer:

39698

Explanation:

Mass= 4.6kg

latent heat= 863

ML= 4.6*863= 39698

approximately = 397 In three significant figures

Answer : The specific latent heat of fusion of ice is, 187.608 J/g

Explanation :

Formula used :

[tex]Q=m\times L_f[/tex]

where,

Q = heat supply = 863 KJ = 863000 J

conversion used : (1 KJ = 1000 J)

m = mass of the substance = 4.6 Kg = 4600 g

conversion used : (1 Kg = 1000 g)

[tex]L_f[/tex] = specific latent heat of fusion = ?

Now put all the given values in the above formula, we get the specific latent heat of fusion of ice.

[tex]863000J=4600g\times L_f[/tex]

[tex]L_f=187.608J/g[/tex]

Therefore, the specific latent heat of fusion of ice is, 187.608 J/g

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