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Calculate the rate of heat transfer by radiation from a car radiator at 111 °C into a 45 °C environment, if the radiator has an emissivity of 0.75 and a 1.6 m^2 surface area.

Respuesta :

Answer:

783.63 Watt

Explanation:

T = 111 degree C = 111 + 273 = 384 K

T0 = 45 degree C = 45 + 273 = 318 K

A = 1.6 m^2

e = 0.75

According to the Stefan's law, the energy radiated per second is given by

[tex]E = \sigma eA\left ( T^{4}- T_{0}^{4}\right )[/tex]

[tex]E = 5.67\times 10^{-8}\times 0.75\times 1.6 ( 384^{4}- 318^{4}\right ))[/tex]

E = 783.63 Watt

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