Respuesta :

Answer:

7.4

Step-by-step explanation:

The information given is in from SAS.

This is a job for law of cosines.

This is the law of cosines [tex]a^2=b^2+c^2-2bc cos(A)[/tex]

The angle A is opposite side a and b,c are the other sides.

So 13 degrees is opposite the y there.

[tex]y^2=16^2+22^2-2(16)(22)\cos(13)[/tex]

Now I'm going to put 16^2+22^2-2*16*22*cos(13) in my calculator:

[tex]y^2=54.04347439[/tex]

Now one more step. To get rid of the square, you need to square root both sides:

[tex]y=\sqrt{54.04347439}=7.351426691[/tex]

Sp the answer is approximately 7.4

jcherry99

Answer:

7.351

I don't know how they have rounded; the closest answer is A

Step-by-step explanation:

The only way I know to do this is with the cos law

y^2 = x^2 + z^2 - 2*x*z cos(Y)

x = 22

z = 16

y = ?

I have serious doubts that this will make a triangle. I ran it though a calculator and it does work -- surprise for me. Substitute the givens.

y^2 = 256 + 484 - 2*10*22*cos(13)

y^2 = 740 - 704*cos(13)

y^2 = 740 - 704*0.9744

y^2 = 740 - 685.95

y^2 = 54.05                                       Take the square root of both sides

y = √54.05

y = 7.351

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