Answer:
B) x < 0 or x > 3
Step-by-step explanation:
[tex]5x-11<-11[/tex] or [tex]4x+2>14[/tex]
Solution:
[tex]5x-11<-11[/tex] add 11 to both sides
[tex]5x<0[/tex] divide both sides by 5
[tex]x<0[/tex]
[tex]4x+2>14[/tex] subtract 2 from both sides
[tex]4x>12[/tex] divide both sides by 4
[tex]x>3[/tex]
x < 0 or x > 3
