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A 100-m-long wire carrying a current of 4.0 A will be accompanied by a magnetic field of what strength at a distance of 0.050 m from the wire? (magnetic permeability in empty space µ0 = 4π ´ 10-7 T×m/A)

Respuesta :

Answer:

1.6 x 10^-5 T

Explanation:

i = 4 A

r = 0.05 m

The magnetic field due to long wire at a distance r is given by

[tex]B = \frac{\mu _{0}}{4\pi }\times \frac{2i}{r}[/tex]

B = 10^-7 x 2 x 4 / 0.05

B = 1.6 x 10^-5 T

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