Respuesta :
Answer : The number of iron atoms present in 4.9 grams of iron are, [tex]5.39\times 10^{22}[/tex]
Explanation : Given,
As we are given that 1.0 grams of iron contains [tex]1.1\times 10^{22}[/tex] iron atoms.
Now we have to determine the number of iron atoms in 4.9 grams.
As, 1.0 gram of iron contains [tex]1.1\times 10^{22}[/tex] iron atoms
So, 4.9 gram of iron contains [tex]\frac{4.9}{1.0}\times 1.1\times 10^{22}=5.39\times 10^{22}[/tex] iron atoms
Therefore, the number of iron atoms present in 4.9 grams of iron are, [tex]5.39\times 10^{22}[/tex]
