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In the first step of hydroboration mechanism, why is an arrow drawn from the pi bond of the alkene to the B atom of the borane reagent signifying the pi electrons are used to make a new C-B bond? See the background information presented with Part I.

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Answer:

The borane reagent acts as a Lewis acid because it is electron-deficient.

Explanation:

The borane reagent is electron-deficient because it does not have a complete octet. Thus, it is electrophilic and accepts donation of the electrons from the alkene.

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