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What is the entropy change of a 29.8 g ice cube that melts completely in a bucket of water whose temperature is just above the freezing point of water?

Respuesta :

Answer:

[tex]\Delta S = 36.55 J/K[/tex]

Explanation:

As we know that entropy change for phase conversion is given as

[tex]\Delta S = \frac{\Delta Q}{T}[/tex]

Here we know that heat required to change the phase of the ice is given as

[tex]\Delta Q = mL[/tex]

here we have

m = 29.8 g = 0.0298 kg

L = 335000 J/kg

now we have

[tex]\Delta Q = 0.0298\times 335000[/tex]

[tex]\Delta Q = 9979.4 J[/tex]

also we know that temperature is approximately same as freezing temperature

so we have

[tex]T = 273 k[/tex]

so here we have

[tex]\Delta S = \frac{9979.4}{273}[/tex]

[tex]\Delta S = 36.55 J/K[/tex]

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