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A softball player is running at 6.9m/s coming into home plate. She leaps and slides the final 3.52 meters to home plate, avoiding being tagged out. If she stops at home plate, what was her acceleration?

Respuesta :

MathPhys

Answer:

-6.76 m/s²

Explanation:

Given:

v₀ = 6.9 m/s

v = 0 m/s

Δx = 3.52 m

Find: a

v² = v₀² + 2aΔx

(0 m/s)² = (6.9 m/s)² + 2a (3.52 m)

a = -6.76 m/s²

Round as needed.

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