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A body accelerates uniformly from rest at 1.5m/s2 for 4s. Calculate the distance covered by the body in the 8s.

Respuesta :

MathPhys

Answer:

48 m

Explanation:

Given:

v₀ = 0 m/s

a = 1.5 m/s²

t = 8 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (0 m/s) (8 s) + ½ (1.5 m/s²) (8 s)²

Δx = 48 m

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