3. A roller coaster car sits at rest at the top of a hill, 23.5 meters tall. What will be the final
velocity of the car at the bottom of the hill?​

Respuesta :

Answer:

21.5 m/s

Explanation:

KE at bottom = PE at top

½ mv² = mgh

v = √(2gh)

v = √(2 × 9.8 m/s² × 23.5 m)

v = 21.5 m/s