The magnitude of AB with initial point A(3,-1) and terminal point B(-2, 6) is 8.6 units.
The distance between two points A(x₁, y₁) and B(x₂, y₂) on the Cartesian plane is given by:
[tex]|AB|=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]
Given AB has initial point A(3,-1) and terminal point B(-2, 6), The magnitude of AB is:
[tex]|AB|=\sqrt{(6-(-1))^2+(-2-3)^2} =8.6\ units[/tex]
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