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how many calories of energy are given off to lower the temperature of 100.0g of iron from 150.0°C to 35.0°C?

Respuesta :

olowookereboyede

Answer:

ΔT = Tfinal − Tinitial = 150°C − 35.0°C = 125°C

given the specific heat of iron as 0.108 cal/g·°C

heat=(100.0 g)(0.108 cal /g· °C )(125°C) =

  100x 0.108x125= 1350 cal

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