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Find the equation of the circle with center at (3,-2) and radius of 3.
a. (x - 3)2 + (y + 2)2 = 9
c. (x-3)2 + (y+ 2) = 3
b. (x+3)2 + (-2)2 = 9
d. (x+3)2 + (-2)2 = 3
Please select the best answer from the choices provided

Respuesta :

Respect3105

Answer:

[tex](x - 3) {}^{2} + (y + 2) {}^{2} = 3 {}^{2} \\ (x - 3) {}^{2} + (y + 2) {}^{2} = 9[/tex]

Answer: The A option is correct.

Good luck!

Intelligent Muslim,

From Uzbekistan.

Answer:

equation of circle=(x-3)^2+(y+2)^2=9

Step-by-step explanation:

given center of circle at (3,-2) and radius=3

equation of circle is [tex](x-x_1)^2+(y-y_1)^2[/tex]=[tex]r^2[/tex]

where r=radius of circle,[tex]x_1[/tex]=3,[tex]y_1[/tex]=-2

eqution of circle=[tex](x-3)^2+(y+2)^2=3^2[/tex]

eqution of circle=[tex](x-3)^2+(y+2)^2[/tex]=9

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