Answer:
(a) 300 ft
(b) 60 ft/s
Explanation:
distance [tex]d=0.5at^{2}[/tex] where a is acceleration and t is time
[tex]d=0.5\times 6\times t^{2}=3t^{2}[/tex]
Also, d=vt where v is the velocity
d=30t
Therefore
[tex]30t=3t^{2}[/tex] hence t=10 s
Substituting t is either formula
d=30t=30*10=300 ft
Also
v=at hence [tex]v=6\times 10=60 ft/s[/tex]