Respuesta :
Answer:
a. [tex]T_f=95.14^{\circ}C[/tex]
b. [tex]T_f=86.4^{\circ}C[/tex]
It is asked for 3 quarts of water because it prevents the temperature drop.
Explanation:
Given:
- mass of frozen cheese, [tex]m_c=255\ g[/tex]
- quantity of water suggested for the given cheese, [tex]m_w=3\ quarts\times 946.35=2839.05\ g[/tex]
- initial temperature of cheese, [tex]T_{ic}=-40^{\circ}\ C[/tex]
- specific heat of cheese, [tex]c_c=0.4\ cal.g^{-1}.^{\circ}C^{-1}[/tex]
- initial temperature of water, [tex]T_{iw}=100^{\circ}\ C[/tex]
a.
- we have specific heat of water, [tex]c_w=1\ cal.g^{-1}.^{\circ}C^{-1}[/tex]
so now, we use the heat equation to find the amount of heat exchange during the process:
[tex]m_c\times c_c\times \Delta T=m_w\times c_w\times \Delta T[/tex]
[tex]255\times 0.4\times (T_f-(-40))=2839.05\times 1\times (100-T_f)[/tex]
[tex]T_f=95.14^{\circ}C[/tex]
b.
when using 1 quart of water:
[tex]255\times 0.4\times (T_f-(-40))=946.35\times 1\times (100-T_f)[/tex]
[tex]T_f=86.4^{\circ}C[/tex]
It is asked for 3 quarts of water because it prevents the temperature drop.