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A train travels north at a speed of 50 m/s.
A passenger walks toward the rear of the
train at a speed of 2 m/s. A person
standing at a train station observes the
motion of the passenger as the train
passes. Which is the apparent speed of the
passenger with respect to the observer at
the train station?
A 2 m/s south
B 48 m/s north
C 50 m/s north
D 52 m/s north

Respuesta :

skyluke89

The apparent velocity is B) 48 m/s north

Explanation:

Here we have a problem of relativity of velocities.

In fact, the train is travelling north at a speed of

[tex]v_t = 50 m/s[/tex]

where this velocity is measured with respect to the ground.

At the same time, a passenger on the train is walking towards the rear (so, south) at a velocity of

[tex]v'=2 m/s[/tex]

where this velocity is measured with respect to the train, which is in motion in the opposite direction.

Therefore, the apparent velocity of the passenger with respect to an observer standing on the ground is:

[tex]v=V_t - v' = 50 - 2 = 48 m/s[/tex]

And the direction is north, since this number is positive.

Learn more about velocity:

brainly.com/question/5248528

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