There are 8 students in each van and 22 students in each bus.
Step-by-step explanation:
Let,
x be the number of students in each van
y be the number of students in each bus
According to given statement;
8x+8y=240 Eqn 1
4x+y=54 Eqn 2
Multiplying Eqn 2 by 2
[tex]2(4x+y=54)\\8x+2y=108\ \ \ Eqn\ 3\\[/tex]
Subtracting Eqn 3 from Eqn 1
[tex](8x+8y)-(8x+2y)=240-108\\8x+8y-8x-2y=132\\6y=132[/tex]
Dividing both sides by 6
[tex]\frac{6y}{6}=\frac{132}{6}\\y=22[/tex]
Putting y=22 in Eqn 2
[tex]4x+22=54\\4x=54-22\\4x=32\\[/tex]
Dividing both sides by 4
[tex]\frac{4x}{4}=\frac{32}{4}\\x=8[/tex]
There are 8 students in each van and 22 students in each bus.
Keywords: linear equation, elimination method
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