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How deep would you have to go
in a mine shaft to reach a pressure
of 2.00 atm? (Assume the density
of air remains a constant
1.29 kg/m^3.)
(Unit = m)​

Respuesta :

MathPhys

Answer:

8010 m

Explanation:

P = Patm + ρgh

2.00 atm = 1.00 atm + (1.29 kg/m³) (9.8 m/s²) h (9.87×10⁻⁶ atm/Pa)

h ≈ 8010 m

Answer:

8,010

Explanation:

The equation you can use to tackle this is:

Pbot=Ptop=ρgh

Rearrange it for h

it is easy

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