Respuesta :
Answer:
In the pile there are 10 quarters and 3 nickels.
Step-by-step explanation:
Given:
Total amount of money = $2.65
Let number of nickels be 'n'.
Also Let number of quarters be 'd'
Now we now that;
nickels 'n' =$0.05
Quarters 'q' = $0.25
So the equation can be framed as;
[tex]0.05n+0.25q = 2.65 \ \ \ \ equation\ 1[/tex]
Now Given:
there are 7 more quarters than nickels.
So we can say that;
[tex]q=n+7 \ \ \ equation 2[/tex]
Now Substituting equation 2 in equation 1 we get;
[tex]0.05n+0.25q = 2.65\\\\0.05n+ 0.25(n+7) =2.65\\\\0.05n+0.25n+1.75= 2.65\\\\0.3n+1.75 =2.65[/tex]
Now Subtracting both side by 1.75 using subtraction property of equality we get;
[tex]0.3n+1.75-1.75=2.65-1.75\\\\0.3n = 0.9[/tex]
Now Dividing both side by 0.3 using division property of Inequality we get;
[tex]\frac{0.3n}{0.3}=\frac{0.9}{0.3}\\\\n = 3[/tex]
Now Substituting the value of n in equation 2 we get;
[tex]q=n+7 = 3+7 =10[/tex]
Hence In the pile there are 10 quarters and 3 nickels.
