Answer:
D. 6
Step-by-step explanation:
Here we are given that a sample of 256 was taken from a population with a standard deviation of 96 centimeters i.e. [tex]\sigma[/tex] = 96 and n = 256.
And we have to calculate the margin of error for a 68% confidence interval.
Firstly from z score% table we observe that at 32% level of significance the z score critical value is given by 0.99744 .
And Margin of error formula is given by ;
[tex]Z_\frac{\alpha}{2}[/tex] * [tex]\frac{\sigma}{\sqrt{n} }[/tex] = 0.99744 * [tex]\frac{96}{\sqrt{256} }[/tex] = 5.98
Approximately, we get Margin of error = 6.
