Answer:
-0.8611796875 V
Explanation:
m = Mass of electron = [tex]9.11\times 10^{-31}\ kg[/tex]
q = Charge of electron = [tex]1.6\times 10^{-19}\ C[/tex]
v = Velocity of electron = [tex]5.5\times 10^5\ m/s[/tex]
The potential difference is given by
[tex]V=\dfrac{K_f}{e}-\dfrac{K_i}{e}\\\Rightarrow V=-\dfrac{\dfrac{1}{2}mv^2}{e}\\\Rightarrow V=-\dfrac{\dfrac{1}{2}\times 9.11\times 10^{-31}\times (5.5\times 10^5)^2}{1.6\times 10^{-19}}\\\Rightarrow V=-0.8611796875\ V[/tex]
The change in electric potential is -0.8611796875 V
