Respuesta :
Answer:
a =3.33 m/s²
Explanation:
given,
initial speed of Plane, u = 0 m/s
final speed of plane, v = 60 m/s
time of the acceleration, t = 18 s
average acceleration of the plane, a = ?
average acceleration is equal to change in velocity per unit time.
[tex]a = \dfrac{v - u}{t}[/tex]
[tex]a = \dfrac{60 - 0}{18}[/tex]
[tex]a = \dfrac{60}{18}[/tex]
a =3.33 m/s²
Hence, average acceleration of the plane is equal to a =3.33 m/s²
Answer:
Explanation:
Given
Airplane runs for a time period of [tex]t=18\ s[/tex]
Airplane takes off with a velocity of [tex]v=60\ m/s[/tex]
It is given that airplane starts from rest i.e. initial velocity [tex]u=0[/tex]
acceleration is the rate of change of velocity thus it is given by
[tex]a=\frac{v-u}{t}[/tex]
[tex]a=\frac{60-0}{18}[/tex]
[tex]a=3.33\ m/s^2[/tex]
Average acceleration for 18 s is [tex]3.33 m/s^2[/tex]
