Answer: The molar mass of the gas is 44.0 g/mol
Explanation:
To calculate the molar mass of the gas, we use the equation given by ideal gas equation:
PV = nRT
Or,
[tex]PV=\frac{w}{M}RT[/tex]
where,
P = Pressure of the gas = 745 mmHg
V = Volume of the gas = 248 mL = 0.248 L (Conversion factor: 1 L = 1000 mL)
w = Weight of the gas = 0.433 g
M = Molar mass of gas = ?
R = Gas constant = [tex]62.364\text{ L.mmHg }mol^{-1}K^{-1}[/tex]
T = Temperature of the gas = [tex]28^oC=[28+273]K=301K[/tex]
Putting values in above equation, we get:
[tex]745mmHg\times 0.248L=\frac{0.433g}{M}\times 62.364\text{ L.mmHg }mol^{-1}K^{-1}\times 301K\\\\M=\frac{0.433\times 62.364\times 301}{745\times 0.248}=44.0g/mol[/tex]
Hence, the molar mass of the gas is 44.0 g/mol
