Answer: 10.1mL
Explanation:
To solve this problem, let's generate the equation:
HCl + AgNO3 —> AgCl + HNO3
Next, we find the amount of AgNO3 in 12mL of the solution.
12mL = 0.012L
If 0.16mol of AgNO3 dissolves in 1L of solution,
Therefore Xmol will dissolve in 0.012L i.e
Xmol of AgNO3 = 0.16x0.012 = 0.00192mol
From the equation, 1mole of AgNO3 required 1mole HCl.
This implies that 0.00192mol of AgNO3 will also require 0.00192mol of HCl.
From this result, we can calculate the Volume of HCl that is needed for the reaction. This is done by:
Molarity = mole /Volume
Molarity = 0.19M
Mole = 0.00192mol
Volume =?
Volume = mole / Molarity
Volume = 0.00192 / 0.19
Volume = 0.0101L = 10.1mL
Therefore the volume of HCl needed is 10.1mL
