FOR A
∠a+75°=180°
∠a=180°-75°
∠a=105°
FOR B
Angle b is the car's turn, 3rd and 4th street are parallel so the corresponding angles have equal measures so ∠b=75°.
FOR C
∠c+75°=180°
∠c=180°-75°
∠c=105°
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In the figure, ∠4 is an exterior angle to AUL.
∠4 = 77°
∠4 = ∠1 +∠2
∠1 +∠2 = 52° +25° = 77°
Substitute the value that we alreay know to find ∠3.
⇒ 77° + ∠3 = 180°
⇒ ∠3 = 180° - 77° = 103°
∠4 is equal to the measures of two nonadjacent interior angles, the sum of angles is always 180° so ∠1 +∠2 + ∠3 = 180°. In summary ∠4=sum of the measures of the two nonadjacent interior angles.
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3(x+2)= 3x+6
(3x+6)+35+52= 180
3x+93=180
x=29
b)3(X+2)
3X+6
3(29)+6=93°
93 +35 +52 = 180°
Hope this helps, have a BLESSED AND WONDERFUL DAY! As well as a great Black History Month & Valentine's day! :-)
- Cutiepatutie ☺❀❤
